https://blog.csdn.net/starfishzh-cnhttps://blog.csdn.net/https://blog.csdn.net/starfish/article/details/10618https://blog.csdn.net/starfish/article/details/10618starfishSat, 06 Jul 2002 23:28:00 +0800https://blog.csdn.net/starfish/article/details/10616https://blog.csdn.net/starfish/article/details/10616starfishMon, 25 Mar 2002 08:50:00 +0800https://blog.csdn.net/starfish/article/details/10598https://blog.csdn.net/starfish/article/details/10598starfishFri, 22 Mar 2002 17:41:00 +0800https://blog.csdn.net/starfish/article/details/10609https://blog.csdn.net/starfish/article/details/10609starfishFri, 22 Mar 2002 17:40:00 +0800b>a>0，现在c筒装满水，问能否在c筒中量出d升水(c>d>0)。若可以，给出方案。解答：所谓模数方程，就是模线性方程，即形如 ax ≡ b (mod c) 形式的方程，其中a,b,c是常数，x是自变量，这个方程表示ax mod c = b mod c，即ax和b模c同余。这个量水问题，用模数方程解比较方便，具]]>https://blog.csdn.net/starfish/article/details/10608https://blog.csdn.net/starfish/article/details/10608starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10607https://blog.csdn.net/starfish/article/details/10607starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10606https://blog.csdn.net/starfish/article/details/10606starfishFri, 22 Mar 2002 17:40:00 +08003，分情况讨论如下：(1) m=n，此时可以按照下面的方案设计（下面S表示野人savage，R表示修道士religious， B表示船boat, ||表示河）方案一：m S ||      (m-c)S |]]>https://blog.csdn.net/starfish/article/details/10605https://blog.csdn.net/starfish/article/details/10605starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10604https://blog.csdn.net/starfish/article/details/10604starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10603https://blog.csdn.net/starfish/article/details/10603starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10602https://blog.csdn.net/starfish/article/details/10602starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10601https://blog.csdn.net/starfish/article/details/10601starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10600https://blog.csdn.net/starfish/article/details/10600starfishFri, 22 Mar 2002 17:40:00 +0800 integer，记为 p = f(s)，其中p是一个整数，s是一个字符串，p就是字符串s在数组中的下标。这样如果需要在数组中定位s，只要直接根据函数p=f(s)就可以计算s的位置。]]>https://blog.csdn.net/starfish/article/details/10599https://blog.csdn.net/starfish/article/details/10599starfishFri, 22 Mar 2002 17:40:00 +0800https://blog.csdn.net/starfish/article/details/10614https://blog.csdn.net/starfish/article/details/10614starfishFri, 22 Mar 2002 17:38:00 +0800https://blog.csdn.net/starfish/article/details/10613https://blog.csdn.net/starfish/article/details/10613starfishFri, 22 Mar 2002 17:38:00 +0800https://blog.csdn.net/starfish/article/details/10612https://blog.csdn.net/starfish/article/details/10612starfishFri, 22 Mar 2002 17:38:00 +0800https://blog.csdn.net/starfish/article/details/10611https://blog.csdn.net/starfish/article/details/10611starfishFri, 22 Mar 2002 17:38:00 +0800https://blog.csdn.net/starfish/article/details/10610https://blog.csdn.net/starfish/article/details/10610starfishFri, 22 Mar 2002 17:38:00 +0800https://blog.csdn.net/starfish/article/details/10617https://blog.csdn.net/starfish/article/details/10617starfishFri, 22 Mar 2002 17:37:00 +0800